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Pololu Step Up Voltage Regulator 1.5A Max I/P, 9V Output

£2.93
(£3.52 incl VAT)
Price in points: 586 points
1062-056
In stock
+

The compact (0.32"×0.515") U3V12F9 switching step-up (or boost) voltage regulator takes an input voltage as low as 2.5V and efficiently boosts it to 9V. The pins have a 0.1" spacing, making this board compatible with standard solderless breadboards and perfboards.

Overview

These boost (step-up) voltage regulators generate higher output voltages from input voltages as low as 2.5V. They are switching regulators (also called switched-mode power supplies (SMPS) or DC-to-DC converters) and have a typical efficiency between 80% to 90%. The available output current is a function of the input voltage, output voltage, and efficiency (see Typical Efficiency and Output Current section above), but the input current can typically be as high as 1.4A. This regulator is also available with a fixed 5V or 12V output.

The regulator’s thermal shutdown prevents damage from overheating, but it does not have short-circuit or reverse-voltage protection.

Features

  • input voltage: 2.5V – VOUT
  • fixed 9 V output with 4% accuracy
  • 1.4 A switch allows for input currents up to 1.4A
  • 2 mA typical no-load quiescent current
  • integrated over-temperature shutoff
  • small size: 0.515" × 0.32" × 0.1" (13 × 8 × 3 mm)

Using the Regulator

Connections

The boost regulator has three connections: input voltage (VIN), ground (GND), and output voltage (VOUT).

The input voltage, VIN, must be at least 2.5 V and should not exceed the output voltage, VOUT. Please be wary of destructive LC spikes that might cause the input voltage to exceed VOUT (see below for more information).

The three connections are labeled on the back side of the PCB, and they are arranged with a 0.1" spacing along the edge of the board for compatibility with solderless breadboards, connectors, and other prototyping arrangements that use a 0.1" grid. You can solder wires directly to the board or solder in either the 3×1 straight male header strip or the 3×1 right-angle male header strip that is included.

Typical Efficiency and Output Current

The efficiency of a voltage regulator, defined as (Power out)/(Power in), is an important measure of its performance, especially when battery life or heat are concerns. As shown in the graph above, this switching regulator typically has an efficiency of 80 to 90%.

The maximum achievable output current is approximately proportional to the ratio of the input voltage to the output voltage. If the input current exceeds the switch current limit (typically somewhere between 1.4 and 2 A), the output voltage will begin to drop. Additionally, the maximum output current can depend on other factors, including the ambient temperature, air flow, and heat sinking.

LC Voltage Spikes

When connecting voltage to electronic circuits, the initial rush of current can cause damaging voltage spikes that are much higher than the input voltage. In our tests with typical power leads (~30" test clips), input voltages above 10 V caused voltage spikes in excess of 20V. You can suppress such spikes by soldering a 33μF or larger electrolytic capacitor close to the regulator between VIN and GND.

More information about LC spikes can be found in our application note, Understanding Destructive LC Voltage Spikes.

Dimensions

Size: 0.32″ × 0.515″ × 0.1″1
Weight: 0.4g1

General specifications

Minimum operating voltage: 2.5V
Maximum operating voltage: 9V
Maximum input current: 1.5 A2
Output voltage: 9V
Reverse voltage protection?: N
Maximum quiescent current: 2mA

Notes:

1 Without included optional headers.
2 Regulator may overheat at lower input currents when VIN is much lower than VOUT. Available output current is a function of VIN, VOUT, and the regulator efficiency.

Manufacturer's Details

Manufacturer's SKU :
2116
Manufacturer:
Pololu

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Hi, i want to power a 9v DC input camera from a 7.3 lithium ion battery. It peaks at about 1750ma for a fraction of a second. I don't have an oscilloscope to determine for how long, but it's pretty quick. Do you think this will manage OK? Cheers. Mike

Asked by mike | 20/10/2013, 15:47 | 1 answer(s)
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